Bonjour,
Does someone know the power of a Stuart D10 ?
Bonjour Dave,
Thank you for this quick reply ! I am a little bit disappointed because I thought it was about 1/4 CV - 180 W
A rough estimate of the power (more precise, a calculation of the theoretically max possible power) can be found as follows:
Determine boiler pressure, and convert from Bar to Pascal (1 bar is 100.000 Pa)
Determine total cylinder displacement and convert that to cubic metres (1 cc = 0,000001 m3)
Determine RPM in revolutions per second.
Power is pressur in Pa x volume in m3 x rotations per second. Outcome is in Watt.
Example:
Stuart D1, bore x stroke 19 mm, 2 cylinders. Displacement (assuming pistonrod is 4 mm) is approx 21 cc or 0,000021 m3
Pressure, assume 4 bar=400000 Pa
Max specced RPM is 2000, which is 33,3 revs per second.
0,000021 x 400000 x 33,3 = appr 280W or 0,38 hp.
Mind you, this is extremely theoretical, because 2000 RPM typically is a free running engine, and due to the pressure loss over the valve chests and steam ports, cylinder pressure is very unlikely to be identical to boilerpressure. The above formula also does not take into account the labour used for discharging the spent steam from the cylinders.
But at 4 bar, and loaded with a prop to turn,say 1000 RPM, 0,10~15 hp could be realistic.